10. HALOGEN DERIVATIVES- part 06 - Mechanism of SN reaction : M
10. HALOGEN DERIVATIVES- part 06 - Mechanism of SN reaction :
Mechanism of SN reaction :
rate = k [CH3Br] [OH ]
a. Nature of substrate :
SN2 :
Do you know ?
Dehydrohalogenation
R2C = CR2 > R2C = CHR > R2C = CH2,
- In a nucleophilic substitution reactions of alkyl halides the halogen atom gets detached from the carbon and a new bond is formed between that electrophilic carbon and nucleophile.
- Covalently bonded halogen is converted into halide ion (X ).
- Two electrons constituting the original covalent bond are carried away by the halogen along with it.
- The halogen atom called ‘leaving group’.
- Leaving group is the group which leaves the carbon by taking away the bond pair of electrons.
- The substrate undergoes two changes during a SN reaction.
- The original C-X bond undergoes heterolysisand a new bond is formed between the carbon and the nucleophile using two electrons of the nucleophile.
- These changes may occur in one or more steps.
- The description regarding the sequence and the way in which these two changes take place in SN reaction is called mechanism of SN reaction.
- The mechanism is deduced from the results of study of kinetics of SN reactions.
- Two mechanisms are observed in various SN reactions -
- SN1 mechanism and
- SN2 mechanism.
- The reaction between methyl bromide and hydroxide ion to give methanol follows asecond order kinetics.
- The rate of this reaction depends on concentration of two reacting species, namely -
- Methyl bromide and
- Hydroxide.
- Hence it is called subtitution nucleophilic bimolecular, SN2.
rate = k [CH3Br] [OH ]
- Rate of a chemical reaction is influenced by the chemical species taking part in the slowest stepof its mechanism.
- In the above reaction only two reactants are present and both are found to influence the rate of the reaction.
- This means that the reaction is a single step reactionwhich can also be called the slow step.
- This further implies that the two changes, namely, bond breaking and bond forming at the carbon take place simultaneously.
- Single step mechanism with simultaneous bond breaking and bond forming.
- Backside attack of nucleophile : This is to avoid steric repulsion and electrostatic repulsion between the incoming nucleophile and the leaving group.
- In the transition state (T.S.) the nucleophile and leaving groups are bonded to the carbon with partial bonds and carry partial negative charge. Thus, the total negative charge is diffused.
- The T.S. contains pentacoordinate carbon havingthree σ (sigma) bonds in one plane making bond angles of 1200 with each other and two partial covalent bonds along a line perpendicular to this plane.
- WhenSN2reaction is brought about at chiral carbon the product is found to have opposite configuration compared to that of the substrate.
- In other words, SN2 reaction is found to proceed with inversion of configuration. This is like flipping of an umbrella. It is known as Walden inversion.
- The inversion in configuration is the result of backside attack of the nucleophile.
- The reaction between tert-butyl bromide and hydroxide ion to give tert-butyl alcohol follows a first-order kinetics.
- The rate of this reaction depends on concentration of only one species, which is the substrate molecule, tert-butyl bromide. Hence it is called substitution nucelophilic unimolecular, SN1.
- Concentration of only substrate appears in the rate equation; concentration of the nucleophile does not influence the reaction rate.
- In other words, tert-butyl bromide reacts with hydroxide by a two step mechanism.
- In the slow step C-X bond in the substrate undergoes heterolysis and in the subsequent fast step the nucleophile uses its electron pair to form a new bond with the carbon undergoing change.
- Two step mechanism.
- Heterolyis of C-X bond in the slow and reversible first step to form planar carbocation intermediate.
- Attack of the nucleophile on the carbocation intermediate in the fast second step to form the product.
- When SN1 reaction is carried out at chiral carbon in an optically active substrate, the product formed is nearly racemic.
- This indicates that SN1 reaction proceeds mainly with racemization. This means both the enantiomers of product are formed in almost equal amount.
- Racemization in SN1 reaction is the result of formation of planar carbocation intermediate.
- Nucleophile can attack planar carbocation from either side which results in formation of both the enantiomers of the product.
a. Nature of substrate :
SN2 :
- The T.S. of SN2 mechanism is pentacoordinateand thus crowded.
- As a result SN2 mechanism is favoured in primary halides and least favoured in tertiary halides.
- It has no steric crowding.
- Bulky alkyl groups can be easily accommodated in planar carbocation See.
- As a result SN1 mechanism is most favoured in tertiary halides and least favoured in primary halides.
- Secondly the carbocation intermediate is stabilized by +I effect of alkyl substituents and also by hyperconjugation effect of alkyl substituents containing α-hydrogens.
- As a result, SN1 mechanism is most favoured in tertiary halides and least favoured in primary halides.
- Tertiary halides undergo nucleophilic substitution by SN1 mechanism while primary halides follow SN2 mechanism.
- Secondary halides react by either of the mechanism or by mixed mechanismdepending upon the exact conditions.
- A nucleophile is a species that uses its electron pair to form a bond with carbon.
- Nucleophilic character of any species is expressed in its electron releasing tendency, which can be corelated to its strength as Lewis base.
- A more powerful nucleophile attacks the substrate faster and favours SN2 mechanism.
- The rate of SN1 mechanism is independent of the nature of nucleophile.
- Nucleophile does not react in slow step of SN1. It waits till the carbocation intermediate is formed, and reacts fast with it.
- SN1 mechanism proceeds via formation of carbocation intermediate.
- A good ionizing solvent, polar solvent, stabilizes the ions by solvation.
- Solvation of carbocation is relatively poor and solvation of anion is particularly important.
- Anions are solvated by hydrogen bonding solvents, that is, protic solvents. Thus SN1 reaction proceeds more rapidly in polar protic solvents than in aprotic solvents.
- Polar protic solvents usually decrease the rateof SN2reaction.
- In the rate determining step of SN2 mechanism substrate as well as nucleophile is involved.
- A polar solvent stabilizes nucleophile (one of the reactant) by solvation. Thus solvent deactivates the nucleophile by stabilizing it.
- Hence aprotic solvents or solvents of low polarity will favour SN2mechanism.
Do you know ?
- Negatively charged nucleophile is more powerful than its conjugate acid. For example R-O is better nucleophile than R-OH.
- When donor atoms are from same period of periodic table, nucleophilicity decreases from left to right in a period. For example H2O is less powerful nucleophile than NH3.
- When donor atoms are from same group of the periodic table, nucleophilicity increases down the group. For example, I is better nucleophile than Cl .
Dehydrohalogenation
- When alkyl halide having at least one β-hydrogen is boiled with alcoholic solution of potassium hydroxide, it undergoes elimination of hydrogen atom from β-carbon and halogen atom from α - carbon resulting in the formation of an alkene. This reaction is called β-elimination (or 1,2 - elimination) reaction.
- As hydrogen and halogen is removed in this reaction it is also known as dehydrohalogenation reaction.
- If there are two or more non-equivalent β-hydrogen atoms in a halide, then this reaction gives a mixture of products.
- Thus, 2-bromobutane on heating with alcoholic KOH gives mixture of but-1-ene and but-2- ene.
- The different products of elimination do not form in equal proportion.
- After studying a number of elimination reactions, Russian chemist Saytzeff formulated an empirical rule given below.
- In dehydrohalogenation reaction, the preferred product is that alkene which has greater number of alkyl groups attached to doubly bonded carbon atoms.
- Therefore, in the above reaction but-2-ene is the preferred product, and is formed as the major product.
- It turned out that more highly substituted alkenes are also more stable alkenes.Hence Saytzeff elimination is preferred formation of more highly stabilized alkene during an elimination reaction.
- The stability order of alkyl substituted alkenes is
R2C = CR2 > R2C = CHR > R2C = CH2,
RCH = CHR > RCH = CH2
Remember...
Do you know ?
- Carbon bearing halogen is commonly called α-carbon (alpha carbon) and any carbon attached to α-carbon is β-carbon (beta carbon).
- Hydrogens attached to β-carbon are β-hydrogens.
Do you know ?
Elimination versus substitution:
- Alkyl halides undergo sunstitution as well as elimination reaction.
- Both reactions are brought about by basic reagent, hence there is always a competition between these two reactions.
- The reaction which actually predominates depends upon following factors.
- Tertiary alkyl halides prefer to undergo elimination reaction where as primary alkyl halides prefer to undergo substitution reaction.
- Bulkier electron rich species prefers to act as base by abstracting proton, thus favours elimination.
- Substitution is favoured in the case of comparatively weaker bases, which prefer to act as nucleophile
- Less polar solvent, high temperature fovours elimination where as low tempertaure, polar solvent favours substitution reaction.
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